Solve, (10p-R^2)^2, (11w+3)^2, (12x^2y^2-3)^2, (13-3)^2
Solve
(10p-r^2)^2
(11w+3)^2
(12x^2y^2-3)^2
(13-3)^2
Answer:
- (10p−r²)²
=(10p)(10p)+(10p)(−r²)+(−r²)(10p)+(−r²)(−r²)
=100p²−10pr²−10pr²+r⁴
=r⁴−20pr²+100p²
- (11w+3)²
=(11w+3)(11w+3)
=(11w)(11w)+(11w)(3)+(3)(11w)+(3)(3)
=121w²+33w+33w+9
=121w²+66w+9
- (12x²y²−3)²
=(12x²y²−3)(12x²y−3)
=(12x²y²)(12x²y²)+(12x²y²)(−3)+(−3)(12x²y²)+(−3)(−3)
=144x⁴y⁴−36x²y²−36x²y²+9
=144x⁴y⁴−72x²y²+9
- (13−3)²
=10*10
=100
#JuneChallenge
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