Solve, (10p-R^2)^2, (11w+3)^2, (12x^2y^2-3)^2, (13-3)^2

Solve
(10p-r^2)^2

(11w+3)^2

(12x^2y^2-3)^2

(13-3)^2

Answer:

  • (10p−r²)²

=(10p)(10p)+(10p)(−r²)+(−r²)(10p)+(−r²)(−r²)

=100p²−10pr²−10pr²+r⁴

=r⁴−20pr²+100p²

  • (11w+3)²

=(11w+3)(11w+3)

=(11w)(11w)+(11w)(3)+(3)(11w)+(3)(3)

=121w²+33w+33w+9

=121w²+66w+9

  • (12x²y²−3)²

=(12x²y²−3)(12x²y−3)

=(12x²y²)(12x²y²)+(12x²y²)(−3)+(−3)(12x²y²)+(−3)(−3)

=144x⁴y⁴−36x²y²−36x²y²+9

=144x⁴y⁴−72x²y²+9

  • (13−3)²

=10*10

=100

#JuneChallenge


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